nice review!!! gotta make sure you still have mad skillz in writing reactions. This is just a D-D reaction from last term.
note that the solubility table (table 4.1) was used to deduce that nickel (II) hydroxide is insoluble.
YES! More mad skillz review:) Remeber how to do these? We figure out how many mol of each reactant we have (use molarity x volume), and then we identify the limiting reactant by converting mol reactant A --> mol B, and vice versa.....
need 0.0600 mol KOH to consume 0.030 mol NiSO4. We don't have enough KOH, so KOH is the limiting reactant.
We can write this as a complete ionic equation using what we know about soluble strong electrolytes...
The point here is this: K+(aq) and SO42-are spectator ions in this reaction - the number of mol of these species doesn't change. Their concentrations change only by dilution. So, we started with 0.0200 mol KOH = 0.0200 mol K+, and the final volume of the solution is 300 mL,
Now, the OH- was found to be the limiting reactant (we did this in part (c), so there is no OH- left in solution.
Since NiSO4 was found to be the XS reactant, we should be able to calculate how much is left in the usual way. We started with 0.03 mol NiSO4, and above we found that we needed 0.01 mol NiSO4 to consume all of the KOH.